6=(t^2-t)/2

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Solution for 6=(t^2-t)/2 equation: 


t in (-oo:+oo)

6 = (t^2-t)/2 // - (t^2-t)/2

6-((t^2-t)/2) = 0

(-1*(t^2-t))/2+6 = 0

(-1*(t^2-t))/2+(2*6)/2 = 0

2*6-1*(t^2-t) = 0

t-t^2+12 = 0

t-t^2+12 = 0

t-t^2+12 = 0

DELTA = 1^2-(-1*4*12)

DELTA = 49

DELTA > 0

t = (49^(1/2)-1)/(-1*2) or t = (-49^(1/2)-1)/(-1*2)

t = -3 or t = 4

(t+3)*(t-4) = 0

((t+3)*(t-4))/2 = 0

((t+3)*(t-4))/2 = 0 // * 2

(t+3)*(t-4) = 0

( t+3 )

t+3 = 0 // - 3

t = -3

( t-4 )

t-4 = 0 // + 4

t = 4

t in { -3, 4 }

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